Gary,
With a tuned output circuit there is a conjugate match between the output
circuit and the feed line. This causes any reflected power to be
re-reflected back to the feed line.
There is no conjugate match between the output circuit and the amplifying
device. It only allows for maximum power transfer.
I cannot picture such a situation. A conjugate match to a feed line
requires a resistive part. A tuned output circuit having significant
resistance would be very lossy.
Could you let me see a schematic of such a circuit, with component
values, so that I can analyze it?
Manfred
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