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Re: [Amps] RE : Another metalwork question

To: craxd1@verizon.net, amps@contesting.com
Subject: Re: [Amps] RE : Another metalwork question
From: Bill Aycock <baycock@direcway.com>
Date: Wed, 03 Aug 2005 23:45:07 -0500
List-post: <mailto:amps@contesting.com>
We (I assume you mean the US) invented the Automobile? Where did you hear that?

BTW- if you want a superb program for conversion of almost any units, go to 
the site set up by Josh Madison:
http://www.joshmadison.com/software/
(It's free!)
Bill
I saw a funny sign near here-"Highway Signs Are Metric for the Next Ten Miles"
Really!

At 08:25 PM 8/3/2005 -0400, Will Matney wrote:

>Jos,
>
>It was Europe that changed on us. When everybody was in the inch system, 
>the US was born, then Europe changed, and wanted us to? We have too many 
>things here made in the inch system to change even though it's being 
>pushed. Actually, I find metric harder than inch. Of course that's 
>probably because that's all I've ever used. Why was the metric system 
>formed and used over the inch system? What country got the ball rolling as 
>I cant remember? It's just as easy for me to say water freezes at 32 deg F 
>than to say it does at 0 deg C, or something 1" long is 25.4 mm. The only 
>thing I despise is having to keep both inch and metric sockets over the US 
>auto manufacturers using metric. That's kind of funny in a way, here we 
>invented the automobile, and we're using metric so folks in Europe and 
>Asia will buy them. Why wont Europe and Asia send the US autos with inch 
>fasteners? We do have it whipped on the speedometers, they have both 
>measurements on them! I know when we (J.H. Fletcher Co.) shipped those 
>roof bolters for the mines to Europe and Asia, they were made with inch 
>fasteners and were accepted. The reason I know is I helped design a bunch 
>of them. Looks to me like what's good for the goose is good for the gander.
>
>Best,
>
>Will
>
>*********** REPLY SEPARATOR  ***********
>
>On 8/4/05 at 12:10 AM hermans wrote:
>
> >Why you guys dont adopt the metric sys.........? Its that more simple
> >for every body.
> >Seems European adopted GMT about a century ago in terms of an exchange
> >......but they'r still in the expectation.
> >
> >Jos
> >
> >-----Message d'origine-----
> >De : amps-bounces@contesting.com [mailto:amps-bounces@contesting.com] De
> >la part de Will Matney
> >Envoyé : mercredi 3 août 2005 1:46
> >À : amps@contesting.com
> >Objet : Re: [Amps] Another metalwork question
> >
> >Bill,
> >
> >Sorry about that! I dont do metric conversions enough to remember
> >correctly sometimes. The 6.45 came from a conversion in a transformer
> >equation and it should have been divide by not multiply. The inches to
> >mm factor is 25.4 (1 inch = 25.4 mm). From the example below 0.045" =
> >1.143 mm. The same equation works, it's just you divide by, not multiply
> >by in the end to convert from one to another. However, for what you want
> >leave dividing 25.4 off at the end and it will be in mm. I know one
> >thing, I'll have to stop trying to think when I've been up so late.
> >
> >BA = (0.0078 * T + 0.0174 * R) * No. of deg. in bend
> >
> >14 Ga = 1.62814 mm
> >
> >For 0" radius, 90 Deg bend in aluminum;
> >
> >(0.0078 * 1.62814 + 0.0174 * 0) * 90
> >
> >(0.01269949 + 0) * 90 =
> >
> >0.01269949  * 90 = 1.14295428" or 1.14295428" / 25.4= 0.0449" (0.045")
> >or for ending pieces of flanges
> >
> >Best,
> >
> >Will
> >
> >*********** REPLY SEPARATOR  ***********
> >
> >On 8/2/05 at 11:29 AM Bill Aycock wrote:
> >
> >>Will-
> >>Where did the 6.45 come from? I think it is wrong.
> >>Bill
> >>
> >>At 07:14 AM 8/2/2005 -0400, Will Matney wrote:
> >>
> >>>Martin, I dont think much really changes as those factors are derived
> >>from
> >>>ratios. You should be able to add a multiplier of 6.45 to the formula
> >to
> >>>get metric sums. Try that to see what you get and substitute MM in
> >place
> >>>of the inch measurements then multiple the sum by 6.45. I think you'll
> >>get
> >>>the same just different measurment systems that way.
> >>>
> >>>BA = (0.0078 * T + 0.0174 * R) * No. of deg. in bend * 6.45
> >>>
> >>>Best,
> >>>
> >>>Will
> >>>
> >>>
> >>>*********** REPLY SEPARATOR  ***********
> >>>
> >>>On 8/2/05 at 5:57 PM Martin Sole wrote:
> >>>
> >>> >Will,
> >>> >
> >>> >Thanks for the info, very useful. Do you have the formula in a
> >suitable
> >>> >form
> >>> >for metric material? Haven't worked in imperial measurements for
> >over 30
> >>> >years and only see it now and again on odd bits of US made kit.
> >>Actually I
> >>> >am going to make a new plenum for my second Alpha and the original
> >is
> >>most
> >>> >certainly made to imperial measurements but nobody here would
> >>understand if
> >>> >I tried to replicate it that precisely so the new one will be made
> >to
> >>> >metric
> >>> >dimensions. Would definitely appreciate the drawing and picture,
> >mail
> >>away.
> >>> >
> >>> >Thanks
> >>> >
> >>> >Martin
> >>> >
> >>> >
> >>> >-----Original Message-----
> >>> >From: amps-bounces@contesting.com
> >[mailto:amps-bounces@contesting.com]
> >>On
> >>> >Behalf Of Will Matney
> >>> >Sent: 02 August 2005 17:29
> >>> >To: amps@contesting.com
> >>> >Subject: Re: [Amps] Another metalwork question
> >>> >
> >>> >Martin,
> >>> >
> >>> >On bending steel, you use 1/2 the material thickness to figure how
> >much
> >>to
> >>> >add in length. In other words you divide the material thickness in
> >half
> >>> >where there would be an imaginary center line (its neutral axis)
> >going
> >>> >trough it. Then when the steel is bent, a radius is formed on this
> >>> >imaginary
> >>> >center line even though the inside bend is a sharp 90 deg bend. So
> >>whatever
> >>> >the distance is around that small radius in the middle of the steel
> >is
> >>the
> >>> >material to be added. Now aluminum is a different story and there is
> >a
> >>> >formula for it too. What happens in aluminum, there is a shrinkage
> >on
> >>the
> >>> >inside radius and a stretching on the outside different than steel.
> >For
> >>> >aluminum see the formula and example below;
> >>> >
> >>> >BA = (0.0078 * T + 0.0174 * R) * No. of deg. in bend
> >>> >
> >>> >14 Ga = 0.0641"
> >>> >
> >>> >For 0" radius, 90 Deg bend in aluminum;
> >>> >
> >>> >(0.0078 * 0.0641 + 0.0174 * 0) * 90
> >>> >
> >>> >(0.00049998 + 0) * 90 =
> >>> >
> >>> >0.00049998 * 90 = 0.045" or about 3/64" or for ending pieces of
> >flanges
> >>> >make
> >>> >it 1/16" from bend line to end.
> >>> >
> >>> >BA = Bend Allowance
> >>> >R = Radius of bend on the inside, not the neutral axis.
> >>> >T = Material thickness
> >>> >
> >>> >I have a pic with this and a drawing if needed I can e-mail it to
> >you.
> >>Hope
> >>> >this helps.
> >>> >
> >>> >Best,
> >>> >
> >>> >Will
> >>> >
> >>> >
> >>> >*********** REPLY SEPARATOR  ***********
> >>> >
> >>> >On 8/2/05 at 2:46 PM Martin Sole wrote:
> >>> >
> >>> >>Well it is actually amp related, or will be at some point I hope
> >but
> >>> >>seeing how there is a great wealth of resource here it seems a good
> >>> >>place to start.
> >>> >>
> >>> >>Some time back I recall seeing an article, might have been in
> >Radcom,
> >>> >>might have been in QST. Think it had to be either one of those two
> >>> >>though. It addressed the process of marking out metalwork for
> >making
> >>> >>enclosures and explained how to allow the correct amount of
> >material
> >>> >>for bends etc. Was within the last year or two I think.
> >>> >>
> >>> >>Just hoping that somebody might recall where this was or maybe
> >point me
> >>> >>to another resource with similar information.
> >>> >>
> >>> >>Tks
> >>> >>Martin HS0ZED
> >>> >>
> >>> >>
> >>> >>
> >>> >>--
> >>> >>No virus found in this outgoing message.
> >>> >>Checked by AVG Anti-Virus.
> >>> >>Version: 7.0.338 / Virus Database: 267.9.7/60 - Release Date:
> >>> >>28/07/2005
> >>> >>
> >>> >>
> >>> >>
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> >>> >
> >>> >
> >>> >
> >>> >
> >>> >--
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> >28/07/2005
> >>> >
> >>> >
> >>> >
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> >>>
> >>>
> >>>
> >>>_______________________________________________
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> >>
> >>Bill Aycock - W4BSG
> >>Woodville, Alabama
> >>
> >>
> >>_______________________________________________
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> >
> >
> >
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Bill Aycock - W4BSG
Woodville, Alabama 


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