If,
RMS voltage times RMS current (both in phase) is the equal to AVERAGE
and PEP is AVERAGE too, so
PEP=RMS voltage times RMS current?
Max.
-----Original Message-----
From: Bill Fuqua [mailto:wlfuqu00@uky.edu]
Sent: Thursday, November 07, 2002 10:10 AM
To: amps@contesting.com
Subject: Re: [Amps] RMS-PEP & 2x8877
PEP is the AVERAGE power for one full cycle calculated at the peak of the
envelope.
There is no RMS power. There is RMS current and RMS voltage. RMS voltage
times RMS current (both in phase) equals
average power.
73
Bill wa4lav
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