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Re: [Amps] peak voltage rating for load cap

To: amps@contesting.com
Subject: Re: [Amps] peak voltage rating for load cap
From: Conrad PA5Y <g0ruz@g0ruz.com>
Date: Sat, 19 Aug 2017 18:43:35 +0200
List-post: <mailto:amps@contesting.com>
Yes exactly Pi L and the intermediate impedance is 350 ohms, so I think I am right to uncomfortable with this little load C.

Regards

Conrad PA5Y


On 19/08/2017 16:52, Vic Rosenthal wrote:
All of you guys are forgetting that he said "PI-L", not PI!

Vic 4X6GP

On 19 Aug 2017, at 16:29, Peter Voelpel <dj7ww@t-online.de> wrote:

Let´s say the SWR is 3 then the load might be 150 ohms.
The peak voltage across the load capacitor will be 775V at 2KW.
That is sqrt3 higher then at SWR1.

73
Peter


-----Original Message-----
From: Amps [mailto:amps-bounces@contesting.com] On Behalf Of Joe Subich,
W4TV

That will give you average (RMS) voltage with SWR = 1:1.  For peak
voltage, multiply by 1.414 (peak voltage of a sine wave):  316 * 1.414
= 447 V.

Your 1200V capacitor will do the job with adequate headroom., when
your system is all tuned and matched.
Multiply the peak voltage by the SWR for worst case peak voltage if
the voltage node occurs on the capacitor - 316 * 1.414 * 3 = 1340V.
A 1200 volt rated capacitor will be marginal in a *system* allowing
for a maximum SWR of 3:1 at 2 KW - it will be barely adequate when
the system is designed for 1500 W (1166 V).


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