To: | amps@contesting.com |
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Subject: | Re: [Amps] peak voltage rating for load cap |
From: | Conrad PA5Y <g0ruz@g0ruz.com> |
Date: | Sat, 19 Aug 2017 18:43:35 +0200 |
List-post: | <mailto:amps@contesting.com> |
Yes exactly Pi L and the intermediate impedance is 350 ohms, so I think
I am right to uncomfortable with this little load C.
Regards Conrad PA5Y On 19/08/2017 16:52, Vic Rosenthal wrote: All of you guys are forgetting that he said "PI-L", not PI! Vic 4X6GPOn 19 Aug 2017, at 16:29, Peter Voelpel <dj7ww@t-online.de> wrote: Let´s say the SWR is 3 then the load might be 150 ohms. The peak voltage across the load capacitor will be 775V at 2KW. That is sqrt3 higher then at SWR1. 73 Peter -----Original Message----- From: Amps [mailto:amps-bounces@contesting.com] On Behalf Of Joe Subich, W4TV That will give you average (RMS) voltage with SWR = 1:1. For peak voltage, multiply by 1.414 (peak voltage of a sine wave): 316 * 1.414 = 447 V.Your 1200V capacitor will do the job with adequate headroom., when your system is all tuned and matched.Multiply the peak voltage by the SWR for worst case peak voltage if the voltage node occurs on the capacitor - 316 * 1.414 * 3 = 1340V. A 1200 volt rated capacitor will be marginal in a *system* allowing for a maximum SWR of 3:1 at 2 KW - it will be barely adequate when the system is designed for 1500 W (1166 V). _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps_______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps _______________________________________________ Amps mailing list Amps@contesting.com http://lists.contesting.com/mailman/listinfo/amps |
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