To: | <amps@contesting.com> |
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Subject: | [AMPS] SWR and line length, etc. |
From: | jono@enteract.com (Jon Ogden) |
Date: | Mon, 4 Oct 99 14:05:19 -0500 |
measures wrote: >>>> I think that the indicated SWR minimum will always correspond to zero >>>> reactance. >> >>No, that's not correct necessarily. A 100 Ohm termination used in a 50 >>Ohm system has no reactive components. Adding a 1/8 wavelength of 50 Ohm >>transmission line will make that 100 Ohm real load look purely reactive. > >? Weird Science. How is that Weird Sceince, O Great One? Or do you say that the Smith Chart is not correct and that all the people throughout the world who use it are wrong? If I have a 50 Ohm piece of coax in a 50 Ohm system and my load is 100 Ohms, at a point 1/8 wavelength toward the exciter, the polar angle of my impedance vector is -90 degrees. This indicates a purely reactive condition with no real component. You end up with the impedance being 0 - j30 Ohms - capacitive. Now if I am wrong, someone please point it out. The Smith Chart is a mapping that you can overlay on an X-Y axis where the Y-axis is the imaginary or reactive component and the X-axis is the real component. If the value of the X coordinate is zero at some particular point that therefore implies that it is a completely reactive point! How is that weird science? 73, Jon KE9NA -------------------------------------------------------------------------- The Second Amendment is NOT about duck hunting! Jon Ogden jono@enteract.com www.qsl.net/ke9na "A life lived in fear is a life half lived." -- FAQ on WWW: http://www.contesting.com/ampsfaq.html Submissions: amps@contesting.com Administrative requests: amps-REQUEST@contesting.com Problems: owner-amps@contesting.com Search: http://www.contesting.com/km9p/search.htm |
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